ALGEBRA A2

Simplify 10p + 5m + 2m + p

Solution

=10p + 5m + 2m + p

=10p + p  + 5m + 2m

= 11p + 7m

Hence 10p + 5m + 2m + p = 11p + 7m

ALGEBRA A1

R - 9 = 2. Find the value of  R.

Suluhu

R - 9 = 2

R – 9 + 9 = 2 + 9

R – 0 = 11

R = 11

Hence  R = 11

AVERAGE A1

Find average of 11 and 17.

Solution

17 + 11 = 28

Total of numbers = 28

Given Numbers = 2

Average = Total of numbers ÷ Given Numbers

                = 28 ÷ 2  

                = 14

Hence average is 14

GEOMETRY-2

Find the value of m in the following figure.

Solution

m + m + 40⁰ = 180⁰

2m + 40⁰ = 180⁰

2m + 40⁰ – 40⁰ = 180⁰ – 40⁰

2m + 0 = 140⁰

2m = 140⁰

2m  = 140⁰

2           2

m = 70⁰

Hence the value of m is 70⁰   

PERIMETER OF A SEMI-CIRCLE-1

Find perimeter of the following semi-circle

Suluhu

Perimeter = ∏D + D

                      2

                   = ( ¹¹22  X ⁷⁰490 )    +  490

                           ₁7          ₁2

                   = (11 x 70 ) + 490

                   = 770 + 490

                   = 1260

Hence Perimeter is  1260 m

PERIMETER OF TRIANGLE-1

Perimeter of the following triangle is 140. Find the value of a.

Solution.

Perimeter = total of all sides

      100 = 2a + 5a + 3a

      100 = 10a

      ¹⁰ 100    = ¹10a

         ₁10         ₁10

 

      a = 10

Hence a is 10

ALGEBRA-4

if  11w = 25; then find w

Solution

11w = 25

11w = 25          [divide by 11 on both sides]

11       11

w = 2³/11 

Hence w = 2³/11