Wednesday, January 20, 2021

ALGEBRA

 

If   1e  =  50; find the value of e.

      23

 

Solution

 

1e  =  50

23

 

123 x 1e  =  50 x  23     multiply by23 both sides.

       123

 

1e = 50 x 23

 

e = 1150                   [because 1e = e]

 

hence e=1150

 

ZAMU YAKO

 

If   1d  =  20; find d.

     14

Saturday, March 8, 2014

DEGREES B10

Find t in the figure below.



Solution

4t +  t + 900 = 1800

5t = 1800 - 900

5t = 900

5t = 900       [dividing by 4 on both sides]
5       5


c = 180

DEGREES B9

Find c in the figure below.


Solution

2c +  c + 900 = 1800

3c = 1800 - 900

3c = 900

3c = 900       [dividing by 4 on both sides]
3       3


c = 300

DEGREES B8

Find a in the figure below.



Solution

3a + 1230 = 1800

3a = 1800 - 1230

3a = 1170

3a = 1170       [dividing by 4 on both sides]
3       3

a = 390


RATIOS C8

If 2: 8 = 10 : m; Find the value of m.

Solution

2   =  10                            [cross multiply]
8        m

2 x m = 10 x 8

2m = 80


2m = 80                      [divide by 2 on both sides]
2        2

m = 40

Hence the value of m is 40


TRY THIS…………


If 8:3 = 11: w; Find the value of w.

DEGREES B7

Find m in the figure below.


Solution

3m + m + 960 + 1080 = 3600

4m + 2040 = 360[collecting like terms]

4m = 3600 - 2040

4m = 1560

4m = 1560       [dividing by 4 on both sides]
4        4

m = 390


RATIOS C7

If 7: 5 = 14:B; Find the value of B.

Solution

7   =  14                            [cross multiply]
5        B

7 x B = 5 x 14

7B = 70


7B = 70                      [divide by 7 on both sides]
7        7

B = 10

Hence the value of B is 10


TRY THIS…………


If 7:2 = 14: c; Find the value of c.