__Solution__*Length=60 cm, Width = 20 cm*

Perimeter
= 2(length + width)

= 2( 60 + 20)

=2 x 80

=160cm

__Hence Perimeter is 160cm__

Find
the perimeter of the following rectangle. (diagram not to scale)

__Solution__

*Length=60 cm, Width = 20 cm*

__Hence Perimeter is 160cm__

Perimeter
= 2(length + width)

= 2( 60 + 20)

=2 x 80

=160cm

If
__1m__ = 50;
find m

8

8

1m
= 50 x 8

m
= 400

If 4y = 32; find y

4y = 32

4 4

y
= 8

= 2 x __22__
x ~~560~~^{80}

= 2 x 22 x 80

= 44 x
80

= 3520m

Area of triangle is 80cm

Area
= __1__ x base x height

2
Let
height = h

80
= __1__ x 40^{ } x h

2
80
= __1__ x ~~40~~^{20} x
h, canceling by 2

80
= 1 x 20
x h

80
= 20h

h
= 4cm

Find
the area of the following figure

Area
= __1__ x base x height

2

base=15cm, height=20cm.

Area
= __1__ x 15 x 20

2

Area
= __1__ x 15 x ~~20~~^{10 } [canceling
by 2]

Area
= 1 x 15 x 10

Area
= 150

Hello. This is a platform prepared for parents, teachers and primary pupils. As we know, mathematics is so challenging. To meet the needs of the basics of mathematics in the primary school level, we have prepared some examples and questions for you. Don't hesitate to give your comments whenever you find it convenient. Welcome all and be blessed.

By Ndamugoba Ivan.

By Ndamugoba Ivan.

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