Find t in
the figure below.

__Solution__
4t + t + 90

^{0}= 180^{0}^{}

5t = 180

^{0 }- 90^{0}^{}

5t = 90

^{0}^{}

__5t__=

__90__

^{0 }[dividing by 4 on both sides]

5 5

**c = 18**

^{0}
Find t in
the figure below.

4t + t + 90^{0} = 180^{0}

5t = 180^{0
}- 90^{0}

5t = 90^{0}

5 5

Find c in
the figure below.

2c + c + 90^{0} = 180^{0}

3c = 180^{0
}- 90^{0}

3c = 90^{0}

3 3

Find a in
the figure below.

3a + 123^{0}
= 180^{0}

3a = 180^{0
}- 123^{0}

3a = 117^{0}

3 3

If
2: 8 = 10 : m; Find the value of m.

8 m

2
x m =
10 x
8

2m
= 80

2 2

m
= 40

If
8:3 = 11: w; Find the value of w.

Find m in
the figure below.

3m + m + 96^{0}
+ 108^{0} = 360^{0}

4m + 204^{0}
= 360^{0 }[collecting like
terms]

4m = 360^{0
}- 204^{0}

4m = 156^{0}

4 4

If
7: 5 = 14:B; Find the value of B.

5 B

7
x B =
5 x 14

7B
= 70

7 7

B
= 10

If
7:2 = 14: c; Find the value of c.

Find a in
the figure below.

2a + 80 =
180^{0}

2a = 180^{0
}- 80^{0}

2a = 100^{0}

2 2

Simplify
20(4k)

=20(4k)

=20
x 4 x k

=(20
x 4) x k

=(80)
x k

=80k

Simplify
18(5e)

If
3: 5 = 9:h; Find the value of h.

5 h

3
x h =
5 x 9

3h
= 45

3 3

h
= 15

If
8:4 = 14: c; Find the value of c.

Find a in
the figure below.

3a + 72 =
180^{0}

3a = 180^{0
}- 72^{0}

3a = 108^{0}

3 3

Find a in
the figure below.

3a + 81 =
180^{0}

3a = 180^{0
}- 81^{0}

3a = 99^{0}

3 3

If
7: 5 = 14 : B; Find the value of B.

5 B

7
x B =
5 x 14

7B
= 70

7 7

B
= 10

If
10:4 = 14: y; Find the value of y.

Simplify
20p + 6m + 5m + 7p

=20p
+ 6m + 5m + 7p

=20p
+ 7p + 6m + 5m ( collecting the like
terms)

=
27p + 11m ( adding the like terms)

Simplify
20p + 7m + 8m + 9p

If
6: 5 = 18 : B; Find the value of B.

5 B

6
x B =
5 x 18

6B
= 90

6 6

B
= 15

If
7:4 = 14: c; Find the value of c.

Find a in
the figure below.

3a + a + 160
+ 40 = 360^{0}

4a + 200^{0}
= 360^{0 }[collecting like
terms]

4a = 360^{0
}- 200^{0}

4a = 160^{0}

4 4

If
6: 5 = 10 : W; Find the value of W.

5 W

6
x W =
5 x 10

6W
= 50

6 6

W
= 8^{2}/6

If
9:3 = 14: c; Find the value of c.

Find
the value of 30 – 100 ÷ 20 x
2

Here
we use BODMAS

1st
we divide, then we multiply, lastly we subtract.

=
30 – 100 ÷ 20 x
2

= 30 – 5
x 2
(after dividing)

=
30 – 10
(after multiplication)

=
20 (then we get 20 after
subtraction)

Find
the value of 120 – 64 ÷ 8 x
8

Find a in
the figure below

3a + 72 + 30
= 180^{0}

3a + 102^{0}
= 180^{0 }[collecting like
terms]

3a = 180^{0
}- 102^{0}

3a = 78^{0}

3 3

If
6: 8 = 11:B; Find the value of B.

8 B

6
x B =
11 x
8

6B
= 88

6 6

B
= 14^{4}/6 = 14^{2}/3

If
7:2 = 11: h; Find the value of h.

Find a in
the figure below

3a + a + 72
+ 20 = 180^{0}

4a + 92^{0}
= 180^{0 }[collecting like
terms]

4a = 180^{0
}- 92^{0}

4a = 88^{0}

4 4

If
3:2 = 11:3B; Find the value of B.

2 3B

3x3B =
11 x
2

9B
= 22

9 9

B
= 2^{4}/9

If
7:2 = 11:4B; Find the value of B.

Find perimeter of the circle below

P = ∏ x D D= diameter

= __22__ x ~~840~~^{120}

= 22 x 120

= 2640m

Find the
perimeter of the square below.

Perimeter =
4 x
side

= 4
x 35

= 140

hence perimeter 140 mm.

Area of triangle is 150cm^{2}.
Find its base if the height is 50cm.

150 = __1__
x base x height

2

Let base = b

150 = __1__ x b^{ } x 50

2

150 = __1__ x b x ~~50~~^{25}, canceling by 2

150 = 1 x b
x 25

150 = 25b

b = 6cm

Area of triangle is 180cm^{2}. Find its base if the height is 60cm.

Perimeter of a rectangle
is 260cm. If its width is 50cm, find its length.

Perimeter = 2(length +
width)

260= 2(L + 50)

260=2L + 100

260-100 = 2L + 100 – 100

160 = 2L+0

160 = 2L

L = 80

Perimeter of a rectangle
is 340cm. If its width is 40cm, find its length.

Find 3/5 of
200 pupils.

Solution

=^{3}/5
x 200

=^{3}/~~5~~
x ~~200~~^{40}

=3 x 40

=120

Find 3/8 of 400
pupils

Area of rectangle is 160cm^{2}.
If its length is 20cm, find its width.

Area = Length x width

Let width=w,

160 = 20
x w

160 = 20w

w = 8cm

Find 3/5 of 400
pupils.

Solution

=^{3}/5
x 400

=^{3}/~~5~~
x ~~400~~^{80}

=3 x 80

=240

Find ^{3}/20
of 800 pupils

Area of rectangle is 80cm^{2}.
if its length is 16cm, find its width.

Area = Length x width

Let width=w,

80 = 16
x w

80 = 16w

w = 5cm

Area of rectangle is 64cm^{2}. if its length is 16cm, find its width.

Evaluate 50 ÷ 2 – 7.

We apply
BODMAS.

= 50 ÷ 2 – 7

= 25 - 7 [after division]

= 18
[after subtraction]

Evaluate 90 ÷ 9 – 16

Perimeter of a rectangle
is 200cm. If its width is 40cm, find its length.

200 = 2(length + width)

200= 2(L + 40)

200=2L + 80

200-80 = 2L + 80 – 80

120 = 2L+0

120 = 2L

L = 60

Perimeter of a rectangle is 300cm. If its width is 50cm, find its length.

Evaluate 60 ÷ 2 – 7

We apply
BODMAS.

= 60 ÷ 2 – 7

= 30 - 7 [after division]

= 23
[after subtraction]

Evaluate 93 ÷ 3 – 1

Area of rectangle is 240cm^{2}.
Find length if width is 10cm.

Area = Length x width

240
= L x 10

240 = 10L

L = 24cm

Area of rectangle is 140cm^{2}. Find length if width is 10cm.

Simplify
11(4k)

=11(4k)

=11
x 4 x k

=(11
x 4) x k

=(44)
x k

=44k

Simplify
18(2k)

Find
the value of 30 – 60 ÷ 20 x
2

solution

Here
we use BODMAS

1st
we divide, then we multiply, lastly we subtract.

=
30 – 60 ÷ 20 x
2

=
30 – 3 x 2 (after dividing)

=
30 – 6
(after multiplication)

=
24 (then we get 24 after
subtraction)

Find
the value of 100 – 60 ÷ 10 x
8

Area of rectangle is 550cm^{2}.
Find length if width is 5cm.

Area = Length x width

550 = L
x 5

550 = 5L

L = 110cm

Hence length is 110cm

Area of rectangle is 90cm^{2}. Find length if width is 5cm.

Find
the value of 11 – 7 + 3 – 1 + 5 – 4

Here
we use BODMAS

There
is only addition and subtraction, We add first before we subtract

=
11 – 7 + 3 – 1 + 5 – 4

=
11 + 3 + 5 – 7– 1– 4 (rearranging
positives and negatives)

=
19 – 7– 1– 4 (dealing
with positives first we get 19)

=
19 – 12 (then we add the
negatives to get -12)

=
7 (then we get 7 after
subtraction)

Find the value of 16 – 7 + 3 – 1 + 3 – 6

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