__Solution__
m + m + 40

^{0}= 180^{0}
2m + 40

^{0}= 180^{0}
2m + 40

^{0}– 40^{0}= 180^{0}– 40^{0}
2m + 0 = 140

^{0}
2m = 140

^{0}^{}

__2m__=

__140__

^{0}

2 2

m
= 70

^{0}

__Hence the value of m is 70__^{0}
m + m + 40^{0} = 180^{0}

2m + 40^{0} = 180^{0}

2m + 40^{0} – 40^{0} = 180^{0} – 40^{0}

2m + 0 = 140^{0}

2m = 140^{0}

2 2

m
= 70^{0}

Find perimeter of the following semi-circle

Perimeter
= ∏__D__ + D

2

= ( ^{11}__22__ X
^{70}__490__ )
+ 490

=
(11 x 70 ) + 490

=
770 + 490

= 1260

Hence
Perimeter is 1260 m

Perimeter of the following triangle is 140. Find the
value of a.

Perimeter = total of all sides

100 = 2a +
5a + 3a

100 = 10a

a = 10

if 11w = 25; then find w

11w = 25

11
11

w = 2^{3}/11

Subscribe to:
Posts (Atom)